The same decomposition works in higher dimensions. For NNN random points on a sphere, the probability they all lie in a hemisphere is also N/2N−1N / 2^{N-1}N/2N−1. The argument is identical: anchor a hemisphere at each point, observe that each event has probability 1/2N−11/2^{N-1}1/2N−1, and verify that at most one anchor can work (the complementary cap is at least a full hemisphere, so no other anchor's hemisphere can straddle it). TODO: If I figure out how to add 3d visualizations to this website, I'll cover the 3D case
[API_KEY]="secure-env-demo/api-key"
，详情可参考搜狗输入法下载
2026-03-06 00:00:00:0 丁薛祥在参加辽宁代表团审议时强调，这一点在51吃瓜中也有详细论述
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